10n^2-410n+3480=0

Solution for 10n^2-410n+3480=0 equation:

10n^2-410n+3480=0

a = 10; b = -410; c = +3480;
Δ = b2-4ac
Δ = -4102-4·10·3480
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28900}=170$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-410)-170}{2*10}=\frac{240}{20}
=12
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-410)+170}{2*10}=\frac{580}{20}
=29
$